65
submitted 2 months ago* (last edited 2 months ago) by recursive_recursion@lemmy.ca to c/mathmemes

Real title:
Differentiation of Differentiation by Zundamon's Theorem

For anyone out of the loop

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[-] gandalf_der_12te 11 points 2 months ago
[-] itslilith 4 points 2 months ago

Wenn wir 5 als Operator definieren, der eine Funktion verfünffacht, dann ist das korrekt (wenn auch etwas cursed)

[-] gandalf_der_12te 6 points 2 months ago
[-] itslilith 4 points 2 months ago

Das ist gar kein Problem, das ist 1

[-] threelonmusketeers@sh.itjust.works 4 points 2 months ago

"d/dr... (d/dr... (d/dr(r)...)"

[-] sga@lemmings.world 2 points 2 months ago

Well I learnt aboout a good channel today, so thanks for sharing. The premise was interesting, and the "presentation" was certianly something

[-] Thelie@sh.itjust.works 2 points 2 months ago

So d/d(d/dx) is then just [-,d/dx]?

this post was submitted on 15 Jun 2025
65 points (100.0% liked)

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