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submitted 2 days ago* (last edited 2 days ago) by recursive_recursion@lemmy.ca to c/mathmemes

Real title:
Differentiation of Differentiation by Zundamon's Theorem

For anyone out of the loop

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[-] sga@lemmings.world 2 points 7 hours ago

Well I learnt aboout a good channel today, so thanks for sharing. The premise was interesting, and the "presentation" was certianly something

[-] gandalf_der_12te 10 points 2 days ago
[-] itslilith 4 points 2 days ago

Wenn wir 5 als Operator definieren, der eine Funktion verfünffacht, dann ist das korrekt (wenn auch etwas cursed)

"d/dr... (d/dr... (d/dr(r)...)"

[-] gandalf_der_12te 6 points 2 days ago
[-] itslilith 4 points 2 days ago

Das ist gar kein Problem, das ist 1

[-] Thelie@sh.itjust.works 2 points 2 days ago

So d/d(d/dx) is then just [-,d/dx]?

this post was submitted on 15 Jun 2025
59 points (100.0% liked)

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