[-] subiprime 13 points 14 hours ago

that would never take off, dont worry. SMELL, on the other hand...

[-] subiprime 8 points 2 weeks ago

some screenshots of youtube videos i found in the wild :3

[-] subiprime 7 points 2 months ago

petition to make an okbuddyrosalyn community here

[-] subiprime 14 points 2 months ago

6 articles?

amateurs...

meanwhile the polish words for "this" and "that":

[-] subiprime 2 points 2 months ago

this is gonna be absolute chaos with all those giant 2-person-tall wooden pikes with sharp metal on top all getting dropped into free fall in such a tightly packed formation :3

...worth it

[-] subiprime 5 points 2 months ago
[-] subiprime 6 points 3 months ago

man i hate it when i walk by a nuclear power plant and get hit with crippling amounts of ionizing radiation and my immune system stops working

...they should really figure out some way to like, keep the radiation inside or something...

[-] subiprime 2 points 3 months ago

is that saddam hussein

44
submitted 4 months ago by subiprime to c/mathmemes
66
submitted 4 months ago by subiprime to c/196
[-] subiprime 2 points 4 months ago

I think this could use a bit more elaboration, since if x-y+y-z < -(|x-y|+|y-z|), then ||x-y|+|y-z|| >= |x-y+y-z| wouldnt be true. This is impossible though since q >= -|q|

[-] subiprime 2 points 4 months ago

I see, thanks! :3

[-] subiprime 3 points 4 months ago

I'm confused about this step in the final condition's proof:

|๐ŸŽ(x) -๐ŸŒ(x)| +|๐ŸŒ(x) - ๐Ÿ‡(x)| >=|๐ŸŽ(x) -๐ŸŒ(x) +๐ŸŒ(x) - ๐Ÿ‡(x)| = |๐ŸŽ(x) - ๐Ÿ‡(x)| since |q| >= q forall q

I can see how it's true by proving that |p| + |q| >= |p + q|, but that's not stated anywhere and I can't figure out how |q| >= q forall q is relevant.

Also, thanks a lot for making/showing a proof :D

[-] subiprime 2 points 4 months ago

i saw this before going to bed and i dreampt mojang actually added this and i was watching hbg highlights videos in the new update

view more: next โ€บ

subiprime

joined 5 months ago