135° for anyone wondering.
correct, just commenting the 100/80 intersection looks like 90/90, i think it was intentionally misleading, classic trying to get you problem
Yes I originally thought 90 but then noticed the absence of a right angle sign. Also 60+40=100 which means the last angle should be 80. Making that perpendicular 100/80
Yes, simple doodle below for anyone wondering.
You start from left, and calculate them 1 by 1, based on the angles that you already know. It is quite simple actually, you just have to know they always add up to 180 (within triangle, and when you “split” the space over a straight line).
you mean to say the right angles aren't right angles? disgusting, get this outta my sight
evil math teacher laughing in background
this diagram does not provide a right angle indicator, and thus should not be assumed as a right angle
yes that's the stupid excuse my math teacher would give
For context: it used to be 675° a few years back so the math checks out.
that's not how global warming works
I got 125.
180-(90-35)=x 180-55=x 125=x
It isn't 90 degrees because the image is misleading. 60+40+y=180. y=80
I hated pictures like this in school. The numbers are just slapped on an inaccurate image and somehow they expect people to ignore the obvious right triangles and just focus on the math part of it.
Fun fact: In Turkey's university admittance exam, all angles have to be absolutely accurate, and measurements have to be scaled down perfectly to the visible shape in a geometry question.
all angles have to be absolutely accurate
To what tolerance, though? Writing math exams has now become an engineering problem.
If it was to scale you could just use a protractor and skip the whole math part, which is the entire part of the lesson…
I don't see that as a downside as long as these two questions are also included.
How many degrees make up the inner angles of a triangle?
How many degrees make up one side of a straight line?
And what’s wrong with that. Utilizing real world solutions to problems is a life skill. Not some obscure formula that you will forget anyway.
Adding and subtracting is a real life solution. Not sure how that is "obscure"
You are being obtuse. You know what I mean by obscure.
Its intended to focus on a specific skill, the other skill can be valid and not be the point of the lesson.
Then they could use decimals so it's unlikely to get it right without calculating, 60.17°, 40.29°, 35.43°
If the student eventually does geometry for money, they'll discover that customer CAD files invariably have some bizarre error like this.
I was scared I forgot basic trig stuff.
It's even easier than going the triangle route.
A four-corner shape always has 360° internally.
So the internal angle of corner X is 360-(60+40+35).
The exterior angle therefore is 360-360-(60+40+35) = 60+40+35 = 135
That's based on the assumption that the two angles in the middle add up to 180, which can't be assumed by inspection alone as demonstrated by the visibly square 80° angle
No, you should completely ignore the bottom half of the center line. You end up with a shape with four turns. Those four internal angles always add to 360.
He is saying your shape might have 5 turns instead of 4 if the bottom line is not actually a line. Though if that was the case, the problem would not be solvable, so I doubt it.
Nice one, forgot this was an option too. You are missing a set of brackets though ;)
I love that every comment focus on the math puzzle. Since the other stuff is clearly uninteresting.
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