What about something like this:
for i in /media/johann/5461-000B/DCIM/100MEDIA/*.AVI; do newpath="$HOME/Public/240321/$(basename "$i" | sed 's/^IMAG/240321_/g')"; ffmpeg -i "$i" -ss 00:00:00 -t 00:00:20 "$newpath" && rm "$i"; done
Awesome! Thanks, I knew there had to be a way!
edit:
This also works:
for i in *.avi; do ffmpeg -i "$i" -ss 00:00:00 -t 00:00:10 ~/Public/test/${i%.*}.avi ; done
But yours is much nicer.
Try this:
for file in ./*
do
echo "$file"
done
To do some substitution operation om the filename you can use Bash Parameter Expansion.
Use another folder instead of name
The input filename changes each time.
find -name "*.avi" | while read file;
do
echo -v "$file"
done
edited
Almost, here is the one that worked:
for i in *.avi; do ffmpeg -i "$i" -ss 00:00:00 -t 00:00:10 ~/Public/test/${i%.*}.avi ; done
Thanks for pointing me in the right direction.
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Distributions include the Linux kernel and supporting system software and libraries, many of which are provided by the GNU Project. Many Linux distributions use the word "Linux" in their name, but the Free Software Foundation uses the name GNU/Linux to emphasize the importance of GNU software, causing some controversy.
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