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WTF 🤦 (sh.itjust.works)
submitted 2 years ago by 0x4E4F@sh.itjust.works to c/mathmemes
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[-] BoxerDevil@lemmy.world 16 points 2 years ago

Can someone smart explain it to dumb me

[-] odium@programming.dev 75 points 2 years ago* (last edited 2 years ago)

Explanation: How did they get from

x + 2 = x - 2

to

(x+2)(x-2)=0?

That's not a valid step.

[-] 520@kbin.social 18 points 2 years ago* (last edited 2 years ago)

To further clarify,

(x+2)(x-2) means to take the result of X+2 and times it with the result of x-2.

While it is common in algebra to bring the other side over, in order to simplify it, this isn't how you'd do it.

Here, you'd either cancel out the X (by removing it on both sides) or the -2 (by adding 2 to both sides) over to make 2=-2 or X+4=X respectively, which are both nonsense equations.

[-] pendingdeletion@lemmy.world 7 points 2 years ago

and times it with the result

and multiply it with the result

[-] 520@kbin.social 5 points 2 years ago* (last edited 2 years ago)
[-] pendingdeletion@lemmy.world 3 points 2 years ago

Not really, no… ā€œtimesā€ is not a verb. You can multiply 2 by 2, and you can express that as ā€œ2 times 2ā€, but it is not correct to ā€œtimes 2 by 2ā€.

[-] 520@kbin.social 3 points 2 years ago
[-] pendingdeletion@lemmy.world 2 points 2 years ago

Not sure what you think the relevance of a Spanish-English translation of the word ā€œmultiplyingā€ has here… but nonetheless, you can see the correct usage of the word ā€œmultiplyā€ versus the word ā€œtimesā€ in my explanation above. For further clarification I would suggest a real dictionary, like Oxford, Meriam-Webster, etc.

I’m sure plenty of people will continue to make the mistake and it will become an accepted variant, though I wouldn’t consider it to be the correct usage of the word. Similar to the word ā€œirregardlessā€, it’s a word, it’s used incorrectly in place of ā€œregardlessā€ very often, and therefore is an accepted variant. It’s just not the correct word to use. This is why I offered you my initial correction.

[-] 520@kbin.social 2 points 2 years ago* (last edited 2 years ago)

Not sure what you think the relevance of a Spanish-English translation of the word ā€œmultiplyingā€ has here

It's a more authoritative answer than a random comment by a grammar nazi.

Also the dictionaries you mentioned aren't great about including common informal language, which is what 'times by' is.

[-] pendingdeletion@lemmy.world 3 points 2 years ago

Yes I’m sure those at Oxford and MW could learn a thing or two from wordreference.com’s Spanish translation, which made the same mistake you did.

Thanks for calling me a nazi though, during otherwise polite conversation… have a good one.

[-] 520@kbin.social 2 points 2 years ago* (last edited 2 years ago)

Thanks for calling me a nazi though, during otherwise polite conversation… have a good one.

I called you a grammar nazi because it's a perfect description of your behaviour in this conversation, right down to a need to be the only one who's right and being unable to tolerate colloquialisms.

https://en.m.wiktionary.org/wiki/grammar_Nazi

https://www.dictionary.com/e/pop-culture/grammar-nazi/

For a grammar nazi you sure don't seem to read all that carefully.

[-] janet_catcus 2 points 1 year ago* (last edited 1 year ago)

they start off with S' though... looks like they pretended to try to derive?

[-] odium@programming.dev 1 points 1 year ago

I thought that was their profile name

[-] janet_catcus 2 points 1 year ago

oh fuck me, you seem to be correct

[-] jerkface@lemmy.ca 1 points 4 months ago

It's also necessary for x to be either 2 or -2 for the equation to have a value of zero.

[-] 0x4E4F@sh.itjust.works 31 points 2 years ago

Almost everything is wrong in his answer.

The correct answer is, it's unsolvable.

X + 2 = X - 2

X - X = - 2 - 2

0 = - 4

[-] olsonexi@lemmy.wtf 18 points 2 years ago

The real correct answer is that it only works mod 4

[-] SpaceNoodle@lemmy.world 10 points 2 years ago

Only the first step is wrong.

[-] 0x4E4F@sh.itjust.works 3 points 2 years ago* (last edited 2 years ago)

Yeah, my bad šŸ‘.

[-] PM_Your_Nudes_Please@lemmy.world 21 points 2 years ago* (last edited 2 years ago)

It’s not solvable using traditional algebra.

Typically you would try to get all of the variables on one side, and all of the numbers on the other.

So in this instance, you’d start by moving them around to get things together:
x+2 = x-2
x+2-x = -2
x-x = -2-2

But then you simplify, and cancel out any variables that need to be cancelled. In this case we see ā€œx-xā€ so that cancels out to 0. And we see -2-2 which simplifies into -4. So the end result is:

0=-4

Which is obviously a nonsense answer. In the original post, homeslice did the first step wrong, moved everything over to the left incorrectly, (inadvertently setting the whole equation equal to 0) and the whole thing was downhill from there; Since the first step of their solution was wrong, everything behind it was also wrong.

[-] 0x4E4F@sh.itjust.works 2 points 2 years ago

You know how you sometimes make a mistake in one line, but after doing a few lines, you go back to actually writing the equation correctly? Happened to me all the time in uni. It's basically because you were thinking of doing the next line or whatever, and you just forgot that a var or const was somewhere in there, or you just didn't copy (or copy it correctly) in the next line, but the memory of that var/const remained in your brain, so after doing a few lines, the equation is now simple enough so your brain knows something should be there, but it's missing. Sure, we almost always caught up with the mistake, go back, correct the last few lines and carry on. But, every once in a while, you don't, and you carry on solving the equation, and you get a correct solution, but from a purely mathematical standpoint, yes, that solution is not correct.

My math proffesor in uni had an interesting take on this. He said, you didn't do 1 mistake and then correct it to get the right answer, but you actually made 2... which is worse... according to him. And I have to say, at that time, I didn't agree, but let's be honest... he is correct. So, he went a lot harder on those students that did this type of mistake than the ones that just made 1 and carried on solving the equation like nothing happened.

[-] janet_catcus 2 points 1 year ago

nah... its still just one error: that of transcribing your process.

it's like a cosmic ray randomly changed a digit in the memory cells that hold the stringbuffer prepared to be printed.

and then the computation carries on with the internal representation of the whole process still with correct data.

i understand your profs pov though

[-] 0x4E4F@sh.itjust.works 2 points 1 year ago

From an engineering standpoint, I don't agree with him. We make errors all the time, it's basically how we learn how to do things the right way (try, fail, repeat). Not to mention rounding errors, we also make GIGANTIC ones (not all the time, but still).

But, he's a mathematician, not an engineer. So, as I said, from a purely mathematical standpoint, yes, he is correct.

[-] janet_catcus 2 points 1 year ago

well, yeah... xD as i said, i understand that pov. if that printout WAS the process, then yes.

and for an alien that only receives that printout milled into a goldbar attached to a satellite: that would be a bummer ;3

[-] DerisionConsulting@lemmy.ca 7 points 2 years ago

There isn't a valid answer to the question.

Ignore the numbers, and just think about this:
Is there a number that you can add 2 to, that would equal the same about as if you subtracted 2 from it?
The answer is no.

So the person, who is pretending to be smart, just did a bunch of fake math.
Also √4 = 2, so the "answer" they have is just them trying to re-write the question x + 2 = x - 2.

[-] 0x4E4F@sh.itjust.works 3 points 2 years ago
[-] rasensprenger@feddit.de 3 points 2 years ago* (last edited 2 years ago)

The square root of x is usually defined as the positive real number that squares to x, so x^2 = 4 => x = +-2 but sqrt(4) = 2, not +-2

The complex sqrt function is multivalued, but that opens a whole other can of worms

[-] digdug@kbin.social 6 points 2 years ago

And even if you allowed sqrt(4) = ±2, it would still be invalid to evaluate it to -2 on one side of the equation, but then use +2 on the other side.

[-] 0x4E4F@sh.itjust.works 1 points 2 years ago

Of course, you can only choose one at a time, not mix and match, lol šŸ˜‚.

[-] 0x4E4F@sh.itjust.works 2 points 2 years ago* (last edited 2 years ago)

Oh yeah, you're right, now I remembered 🤦. Been a while šŸ˜‚, almost 20 years.

this post was submitted on 22 Jan 2024
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Math Memes

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