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submitted 11 months ago by favrion@lemmy.world to c/math@lemmy.world

Out of 5 six-sided dice, what is the probability of landing 1 of one number and 4 of one other number?

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[-] surewhynotlem@lemmy.world 2 points 11 months ago

1/1 * 5/6 * 2/6 * 1/6 * 1/6

Right?

First die is some number. Second die is anything but that number. Third die needs to be one of the first two. Fourth and fifth need to be whichever has doubled up already.

[-] TheOrs@lemmy.world 3 points 11 months ago

No, because we still get that one of the first two dice is the different one. Since there are 5 places for the different die to be, and it can only be in one of these places, we can just sum up the probabilities of the different die being each of the 5 rolls. Since all these probabilities are the same, we get 5*(probability of the different die roll being the last one).

[-] surewhynotlem@lemmy.world 2 points 11 months ago

Can you show the math please? I don't follow the words.

[-] TheOrs@lemmy.world 1 points 11 months ago

511/61/61/65/6 Which corresponds to (Number of rolls)(any number)(same number)(same number)(same number)(different number)

this post was submitted on 18 Nov 2023
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