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[-] elvith@feddit.org 39 points 2 weeks ago
[-] lambda@programming.dev 14 points 2 weeks ago

Now see, you need the other method. IsNegativeEven()

[-] sus@programming.dev 9 points 2 weeks ago

We can avoid expensive branches (gasp) by using some bitwise arithmetic to achieve the so-called "absolute value", an advanced hacker technique I learnt at Blizzard. Also unlike c, c# is not enlightened enough to understand that my code is perfect so it complains about "not all code paths returning a value".

private bool IsEven(int number)
{
    number *= 1 - 2*(int)(((uint)number & 2147483648) >> 31);
    if (number > 1) return IsEven(number - 2);
    if (number == 0) return true;
    if (number == 1) return false;
    throw new Exception();
}
[-] UnknownSoul@programming.dev 2 points 2 weeks ago

Nice, now we just need another function to find odd numbers, cause not all numbers are even you know.

this post was submitted on 15 Jul 2025
291 points (100.0% liked)

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