5

Second representation requires at least 6 bits to represent numbers between 0 to 59. But 5 bits are not just enough - 2^5^ = 32, which can only represent from 0 up to 31 seconds.

According to K.N. King:

You may be wondering how it 's possible to store the seconds - a number between 0 and 59 in a field with only 5 bits. Well. DOS cheats: it divides the number of seconds by 2, so the seconds member is actually between 0 and 29.

That really makes no sense?

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[-] MachineFab812@discuss.tchncs.de 1 points 2 weeks ago

Pretty sure no one here was worried about what was or wasn't possible, just the method that was used in this specific instance.

this post was submitted on 04 Oct 2024
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