485
Physics rule (slrpnk.net)
submitted 3 months ago by Track_Shovel@slrpnk.net to c/196
you are viewing a single comment's thread
view the rest of the comments
[-] ji17br@lemmy.ml 3 points 3 months ago

You want to figure out distance per second. One way to do this is calculate distance apart at t=0,1,2…

The difference between each point would be the average speed over that second.

Using sqrt(b^2+g^2):

t0 = 0 t1 = 1.554m
s1 = (1.554m-0m)/1s = 1.554m/s t2 = 3.108m
s2=(3.108m-1.554m)= 1.554m/s

As you continue this you will see they travel at a constant speed apart from each other. The reason this is working is because you need to divide distance by time. Dividing by 1 second won’t change the value of the number after you subtract. If you notice you can do (t2-t0)/2s and also get the same answer.

[-] dabaldeagul@feddit.nl 1 points 3 months ago

Ahhh okay, thanks

this post was submitted on 28 Aug 2024
485 points (100.0% liked)

196

16744 readers
1868 users here now

Be sure to follow the rule before you head out.

Rule: You must post before you leave.

^other^ ^rules^

founded 2 years ago
MODERATORS