485

submitted 3 months ago by Track_Shovel@slrpnk.net to c/196

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[-] havid_dume@lemmy.ml 5 points 3 months ago

Each of their speeds is constant, but different, and they're walking in different directions.

[-] luciole@beehaw.org 13 points 3 months ago

Their distance is the hypotenuse of a triangle with sides 5t and t which will be root((5t)^2^ + t^2^). So the distance at time t of the ex lovers will be root(26) × t. You can basically grasp intuitively that the speed is indeed constant and equals to the root(26)=5.1 ft/sec. Technically you’d use the derivative power rule to drop the t and get the speed.