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submitted 1 year ago* (last edited 1 year ago) by Ti_Ka to c/godot@programming.dev

As in, for any two Transform3D objects A and B i might encounter does Godot (4.1) always return A * B == B * A as true? Alternatively is it approximately commutative, ie (A * B).is_equal_approx(B * A), in case there are situations where floating point imprecision messes the exact equality up.

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[-] david@feddit.uk 5 points 1 year ago

No.

If you rotate 180 degrees about the x axis and then 180 degrees about the line y=x, you get a rotation anticlockwise by 90 degrees about the z axis.

If you do it the other way round, the rotation is the opposite direction (clockwise).

They only commute in quite specific circumstances.

[-] Ti_Ka 1 points 1 year ago* (last edited 1 year ago)

Ok so it seems like they don't commute? I asked the question in part because i wanted to do something like:

const base_transform : Transform3D = <some transform>

func get_base_transform(node : Node3D) -> Transform3D:
    return node.transform * base_transform

func set_base_transform(node : Node3D, transform : Transform3D) -> void:
    node.transform = base_transform.affine_inverse() * node.transform

and i wanted to be sure that if i do set_base_transform(some_node, some_transform) i'd be guaranteed to get that get_base_transform(some_node) == some_transform afterwards. But when i tried it the above code did not work out, at least i didnt get the result i expected. But when i flipped it so that set_base_transform did node.transform = node.transform * base_transform.affine_inverse() instead it did work out. Its still not hard proof though, maybe something else was messed up the first time, or it only looks like it works now and i'll discover the transform still isn't what i wanted it to be. Or they do commute but only under some constriction like no scale on any axis or something and i just happened to fulfill it with all the ones i used in my test.

So it would still be good to know for sure whether/when Transform3D's commute.

EDIT: I accidentally wrote the first line wrong, it said that they do commute. When actually the experience i had with it working only after both functions did their multiplications in a compatible order should indicate that they don't commute.

[-] 133arc585@lemmy.ml 3 points 1 year ago* (last edited 1 year ago)

I'm writing this as someone who has not done much with Godot, but from the mathematical standpoint, two Transform3Ds do not commute in general. There are situations in which they will commute, though. If they are both pure rotations, they will commute if their rotation axes are the same.

Edit to add: This was based on thinking about a Transform3D as a transformation matrix acting on R^3^.

[-] o11c@programming.dev 1 points 1 year ago

I likewise don't really use Godot, but for graphics in general, the 4th coordinate is important, even if it is "usually" 1. It's most obvious to correctly interpolate near the poles of a sphere with a single rectangular texture, but think for a minute what "near" means.

Back to the main point though: the important things we normally rely on for matrix math are associativity (particularly, for exponentiation!) and anticommutativity (beware definitions that are sloppy about "inverse").

[-] 133arc585@lemmy.ml 1 points 1 year ago* (last edited 1 year ago)

but for graphics in general, the 4th coordinate is important, even if it is “usually” 1.

Who said it isn't? Transformation matrices acting on R^3^ are 4x4 (since transformation matrices acting on R^n^ are of dimension n+1 in general), whether they're full rank or not.

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this post was submitted on 12 Jul 2023
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