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Other 196's:
Why do you assume it was a pointer type? There's no types. Why do you assume C either? This is pseudo code to illustrate pointer offsets
Because afterwards you said
arr[n]
. By conventionn
is definitely an integer and if arr is also, say, an integer, you getBecause you didn't write
^(@arr+0)
(Not sure that's even valid though my Pascal is very rusty).Granted. But then it's still Pseudo-C, not Pseudo-Pascal or Pseudo-Whitespace.
It's pseudo-nothing
It conveys a point, which you got, and if you decide to invent a syntax and bicker on it it's just you
Really pointless discussion