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Gotta follow that rule (sh.itjust.works)
submitted 1 year ago by ephrin@sh.itjust.works to c/196
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[-] NorthWestWind@lemmy.world 33 points 1 year ago

The circle could've been done in one equation

[-] Ashelyn 37 points 1 year ago

One equation, sure, but not in one valid function (without making it parametric anyways)

[-] NorthWestWind@lemmy.world 4 points 1 year ago

x^2^+y^2^=1
or, in this case
(x-2)^2^+(y-2)^2^=1

[-] SkybreakerEngineer@lemmy.world 19 points 1 year ago

Not valid functions

[-] Ashelyn 12 points 11 months ago
[-] NorthWestWind@lemmy.world 2 points 11 months ago

Ok you're right

[-] bob_lemon@feddit.de 3 points 1 year ago

A that's a single equation alright. But as the previous poster pointed out, it's not a function.

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this post was submitted on 09 Jan 2024
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