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submitted 1 year ago* (last edited 1 year ago) by andioop@programming.dev to c/programming_horror@programming.dev
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[-] recursive_recursion@programming.dev 11 points 1 year ago* (last edited 1 year ago)

modulo

pseudocode:

if number % 2 == 0
  return "number is even" (is_num_even = 1 or true)
else
  return "number is odd" (is_num_even = 0 or false)

plus you'd want an input validation beforehand

[-] mac@programming.dev 18 points 1 year ago* (last edited 1 year ago)

who needs modulo when you can get less characters out of

while (number > 1) {
  number -= 2;
}
return number;

very efficient

edit: or theres the trusty iseven api

[-] nullPointer@programming.dev 8 points 1 year ago

here is somewhat less:

return (number % 2) == 0;

[-] pivot_root@lemmy.world 10 points 1 year ago
[-] venoft@lemmy.world 8 points 1 year ago* (last edited 1 year ago)

This is the way. Modulo takes too long to compute, bitwise compare should be a lot faster.

return !(number & 0x1);
[-] recursive_recursion@programming.dev 5 points 1 year ago* (last edited 1 year ago)

oh shit yo

this comment chain is pretty awesome, I learned a lot from this thanks!

[-] perviouslyiner@lemm.ee 2 points 1 year ago

are the negative numbers all even?

[-] Vex_Detrause@lemmy.ca 4 points 1 year ago
#You are an input. You have value! You matter!
if number % 2 == 0
  return "number is even" (is_num_even = 1 or true)
else
  return "number is odd" (is_num_even = 0 or false)

Am I doing it right? /S.

[-] PoolloverNathan@programming.dev 5 points 1 year ago

Don't put nbsps in code blocks, they show up literally.

[-] misophist@lemmy.world 3 points 1 year ago

Name doesn't check out.

[-] RandomVideos@programming.dev 2 points 1 year ago

This code is terrible. If you input 10.66 it returns "number is odd

It should be:

if number % 2 == 0
  return "number is even" (is_num_even = 1 or true)
else
  return "number is not even" (is_num_even = 0 or false)
this post was submitted on 07 Dec 2023
198 points (100.0% liked)

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