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submitted 2 months ago by sirico@feddit.uk to c/programmerhumor@lemmy.ml

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[-] Aedis@lemmy.world 34 points 2 months ago

I'm partial to a recursive solution. Lol

def is_even(number):
    if number < 0 or (number%1) > 0:
        raise ValueError("This impl requires positive integers only") 
    if number < 2:
        return number
    return is_even(number - 2)

[-] tetris11@lemmy.ml 18 points 2 months ago* (last edited 2 months ago)

I prefer good ole regex test of a binary num

function isEven(number){
   binary=$(echo "obase=2; $number" | bc)
   if [ "${binary:-1}" = "1" ]; then
         return 255
   fi
   return 0
}

[-] barubary@infosec.exchange 5 points 2 months ago

@tetris11 @Aedis More like:

isEven() {    case "$1" in        *[02468]) return 0;;        *) return 1;;    esac;}

(If all the line breaks are gone from this code snippet, blame Lemmy. It looks fine here.)

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this post was submitted on 15 Jul 2025

409 points (100.0% liked)

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