submitted 1 week ago by Corsair@programming.dev to c/linux@programming.dev

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Hi,

I would like to found a regex match in a stdout

stdout

 /dev/loop0: [2081]:64 (/a/path/to/afile.dat)

I would like to match

/dev\/loop\d/

and return /dev/loop0

but the \d seem not working with awk ... ?

How to achieve this ? ( awk is not mandatory )

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[-] 4am@lemm.ee 1 points 1 week ago

Why are you making a literal out of the + operator? This will not work.

grep -o ‘/dev/loop[0-9]+’

[-] pelya@lemmy.world 3 points 1 week ago

Because it does work, you need grep -E for '+' to work without escaping. Also, your quotes are wrong, ‘ should be ' .

this post was submitted on 08 Jun 2025

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