1111
Tell me the truth ...
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This was gonna be my response to OP so I'll offer an alternative approach instead:
Why not
if (f & (F_1 | F_3)) {
? I use this all the time in embedded code.edit: never mind; you’re checking for both flags. I’d probably use
(f & (F_1 | F_3)) == (F_1 | F_3)
but that’s not much different than what you wrote.