Day 5: Print Queue

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[-] mykl@lemmy.world 2 points 1 month ago* (last edited 1 month ago)

Oh my. I just watched yernab's video, and this becomes so much easier:

# Order is totally specified, so sort by number of predecessors,
# check to see which were already sorted, then group and sum each group.
Data ← ⊜(□⊜□⊸≠@\n)⊸(¬⦷"\n\n")"47|53\n97|13\n97|61\n97|47\n75|29\n61|13\n75|53\n29|13\n97|29\n53|29\n61|53\n97|53\n61|29\n47|13\n75|47\n97|75\n47|61\n75|61\n47|29\n75|13\n53|13\n\n75,47,61,53,29\n97,61,53,29,13\n75,29,13\n75,97,47,61,53\n61,13,29\n97,13,75,29,47"
Rs   ← ≡◇(⊜⋕⊸≠@|)°□⊢Data
Ps   ← ≡⍚(⊜⋕⊸≠@,)°□⊣Data
⊕(/+≡◇(⊡⌊÷2⧻.))¬≡≍⟜:≡⍚(⊏⍏/+⊞(∈Rs⊟)..).Ps

this post was submitted on 05 Dec 2024

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