394
Rule (lemmy.blahaj.zone)
submitted 1 month ago by Persona3Reload to c/196
you are viewing a single comment's thread
view the rest of the comments
[-] superkret@feddit.org 8 points 1 month ago

What if the remainder is greater than the first, but not less than the latter?

Like, for example, 1?

[-] prime_number_314159@lemmy.world 3 points 1 month ago

Then you should return false, unless the remainder is also greater than or equal to the twenty second root of 4194304. Note, that I've only checked up to 4194304 to make sure this works, so if you need bigger numbers, you'll have to validate on your own.

[-] fartripper@lemmy.ml 5 points 1 month ago

i hate to bring this up, but we also need a separate function for negative numbers

[-] prime_number_314159@lemmy.world 1 points 1 month ago

You can just bitwise AND those with ...000000001 (for however many bits are in your number). If the result is 0, then the number is even, and if it's 1, then the number is odd. This works for negative numbers because it discards the negative signing bit.

this post was submitted on 31 Oct 2024
394 points (100.0% liked)

196

16724 readers
2182 users here now

Be sure to follow the rule before you head out.

Rule: You must post before you leave.

^other^ ^rules^

founded 2 years ago
MODERATORS