Pl/1 did it right:

Dcl 1 mybools, 3 bool1 bit(1) unaligned, 3 bool2 bit(1) unaligned, … 3 bool8 bit(1) unaligned;

All eight bools are in the same byte.

...or you can be coding assembler - it's all just bits to me

This guy never coded in KEIL C on an 8051 architecture. They actually use bit addressable RAM for booleans. And if you set the compiler to pass function parameters in registers, it uses the carry flag for the first bit or bool type parameter.

Redundancy is nice in the event of bitflip errors

7 Shades of Truth

Now store the numbers (array):

0 0 0 1 0 1 1 2

think 8 bytes???