find /home/user -type f -perm /u+x -not -path "/home/user/Documents" -exec cp {} ~/Documents \;

Run it without exec -parameter to get a list of files affected, I'd guess that that will catch more than you want as it only checks that it's a normal file and has the excecutable -bit on. To get only bash-scripts you'd first need to get a list of files with find and then check if it's a script with something (grep or maybe file should work) and copy based on that result, but it shouldn't be too difficult to write a script for it.

find ~ -type f -executable

will give you a list of all executable files You can probably use find’s -exec to move them all.

grep -rl '#!/bin/bash' . | xargs -I {} cp {} /path/to/destination/

assuming you have a GNU toolchain you can use the find command like so:

find . -type f -executable -exec sh -c '
case $( file "$1" ) in (*Bourne-Again*) exit 0; esac
exit 1' sh {} \; -print0 | xargs -0 -I{} cp {} target/

This first finds all executable files in the current directory (change the “.” arg in find to search other dirs), uses the file command to test if it’s a bash file, and if it is, pipes the file name to xargs which calls cp on each file.

note: if “target” is inside the search directory you’ll get output from cp that it skipped copying identical files. this is because find will find them a free you copy them so be careful!

note 2: this doesn’t preserve the directory structure of the files, so if your scripts are nested and might have duplicate names, you’ll get errors.

identify

find DIR -executable

copy

find DIR -executable -exec cp {} TARGETDIR \;

Combine grep -l to find files with the shebang and cp to copy them to your docs folder. You can one-liner pipe or save the grep results to file and iterate. If the directories are nested and some of these files have the same name, they'll conflict if you don't include most of the original path in the cp target.

If you need them to be executable I think I'd use find first.