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[-] Sonotsugipaa@lemmy.dbzer0.com 4 points 4 months ago

Isn't it more of a blue shift / red shift situation, rather than scattering?

[-] kaedon@beehaw.org 8 points 4 months ago* (last edited 4 months ago)

There is a very small amount of red shift. If you were standing on the equator watching a sunset, then your radial velocity relative to the sun is only ~461m/s. So the green light from the sun 550nm would be red shifted by +0.0008nm. That little red shift wouldn't be noticeable. However, as the sun sets there's a lot more atmosphere in the way, which scatters blue light more than red light (Why the sky is blue). Also in a sunrise you are moving towards the sun, so sunrises would be blue! :P

[-] Zink@programming.dev 1 points 4 months ago

Are you sure those numbers are right? The proportions of 550nm/0.08nm and c/461m/s are very different.

[-] kaedon@beehaw.org 3 points 4 months ago

Oops you're right missed a few zeros.

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this post was submitted on 21 Jun 2024
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