submitted 5 days ago by m_f@midwest.social to c/loops@midwest.social

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[-] Kraiden@kbin.earth 5 points 4 days ago

I'm sorry, but even without knowing about the mod operator, this is inefficient and over engineered. Why have a loop at all?

fun isEven(n: Int){
    return n == abs(n)
}

no loop required...

having said that, I can totally see how that was missed in a high pressure interview. I hate interviews like that!

edit: Ha ha... isEven...not isPositive... I'm tired. ignore me!

[-] petrol_sniff_king 8 points 4 days ago

I'm not following.
n == abs(n) only tells you if it's positive.

[-] Kraiden@kbin.earth 6 points 4 days ago

yes, I'm being a dumb tonight. I'm completely wrong

[-] petrol_sniff_king 3 points 4 days ago

Haha, s'all good, yo.

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this post was submitted on 21 Dec 2024

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